Python Multiple Condition Between Two List

I'm using python 3 and I need to check 3 variables in different list. I want to print data if username age lang are different from the other list Here is my code : list1 = [] list2

Solution 1:

You can use set to hash a sequence of tuple elements from one list. The logic below works specifically when names are in list2 can be of the format name-a, name-b, etc, and you are only interested in the first part.

from operator import itemgetter

def field_getter(x):
    i, j, k = itemgetter('username', 'age', 'lang')(x)
    return i.split('-')[0], j, k

item_set = set(map(field_getter, list2))

for d in list1:
    d_fields = field_getter(d)
    if field_getter(d) not in item_set:
        print(*d_fields)

alice 25 IT
carole 40 FR
mick 20 US

Solution 2:

You should output the record only if it's not found in list2, so you should use the for-else construct to print after you've made sure there's no entry in list2 with all 3 fields passing the equality tests (rather than inequality tests):

for l1 in list1:
    username = l1['username']
    age = l1['age']
    lang = l1['lang']

    for l2 in list2:
        if username in l2['username'] and l2['age'] == age and l2['lang'] == lang:
            breakelse:
        print(str(username) + ' ' + str(age) + ' ' + str(lang))

This outputs:

alice 25 IT
carole 40 FR
mick 20 US

Solution 3:

Sort the items with a comparison rule on the three fields. The identical records will appear next to each other and a single loop will be enough.